■ 定積分∫[-2,2] | x^(2)-1 | dx　の値を求めよ。

解答
∫[-2,2] | x^(2)-1 | dx＝∫[-2,-1] x^(2)-1 dx +∫[-1,1] -x^(2)+1 dx + ∫[1,2] x^(2)-1 dx
∫[-2,2] | x^(2)-1 | dx＝[(x^(3)/3)+x][-2,-1] +[(-x^(3)/3)+x][-1,1]+[(x^(3)/3)+x][1,2]=(-4/3)-(-14/3)+(4/3)-(-2/3)+(14/3)-(4/3)=(28/3)-(2/3)=26/3